假设P=0.02AQL值
总量500 一般检验Ⅱ级水平 0.1125AC00.080031224RE10.1580AC00.198885RE10.2550AC00.316968RE1P(0.95)P(0.10)0.00450.04770.00710.070.01650.1030.02780.129AQL0.6511.52.5n80505050Ac1123假设N500500500500P =P1=AQL0.6511.52.50.020.1n125505050Ac1123Re2234OR10.6010.626.244.0.391746998
0.432AC00.52388314RE10.6580AC10.522973503RE2AC10.735771394150RE2Re2234Pa0.52297350.73577140.92157230.9822419Pa=0.950.9492036650.95066210.9503805320.949933303Pa=0.100.100344260.1007718330.0998461290.099158298αβ0.47702650.0019420.2228610.028632080.078427750.07794290.017758080.138565151.550AC20.921572252RE32.550AC30.982241919RE4450AC50.999521783RE6OR10.6010.626.244.α0.47702970.22286060.0784277480.017758081β0.0019420.028632080.07794290.13856515假设P1=
0.1
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